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1Simple models

Now that we have a model to describe the dynamics of the Universe, let’s calculate its evolution in a few simple cases for practice.

Flat universe, matter only

Let’s start with the case of a flat Universe containing only non-relativistic matter. This is the so-called Einstein-de Sitter model. It is the simplest one could think of in 1930. The first Friedmann equation is written:

3a˙2a2=8πGρm=8πGρm0(a0a)3(a˙)2=8πGρm0a03/3a=H02Ωm0a03a\begin{align*} & 3 \frac{\dot{a}^2}{a^2} = 8\pi \GN \rho_m = 8 \pi \GN \rho_m^0 \left(\frac{a_0}{a}\right)^{3} & \Leftrightarrow (\dot a)^2 = 8 \pi \GN \rho_m^0 a_0^3 / 3 a = H_0^2 \Omega_m^0 \frac{a_0^3}{a} \end{align*}

Before integrating this differential equation, let us remember that the energy density parameters are linked by a closure relation (94). Consequently, in a flat Universe with only matter, we have Ωm0=1\Omega_m^0=1. Let’s now integrate the differential equation between 0 and an arbitrary scale factor aa:

0aaa0daa0=0tH0dt23(a(t)a0)3/2=H0t\int_0^{a}\sqrt{\frac{a'}{a_0}} \frac{\dd a'}{a_0} = \int_0^t H_0 \dd t' \Rightarrow \frac{2}{3}\left(\frac{a(t)}{a_0}\right)^{3/2} = H_0 t
a(t)a0=(32H0t)2/3\Rightarrow \frac{a(t)}{a_0} = \left( \frac{3}{2}H_0 t\right)^{2/3}

with at the beginning of the Universe t=0t=0 when a=0a=0. We have thus obtained a direct relation between the scale factor and the age of the Universe.

Flat universe, radiation only

By similar reasoning, we show that for a flat Universe dominated by radiation we have a different evolution of the scale factor:

a(t)a0=(2H0t)1/2\frac{a(t)}{a_0} = \left( 2 H_0 t\right)^{1/2}

Empty universe (Milne)

Suppose that the Universe is empty, or at least with a total energy density much lower than the critical density. Then the Universe must be curved since in this case:

Ωk0=1Ωm0Ωr0ΩΛ01\Omega_k^0 = 1 - \Omega_m^0 - \Omega_r^0 - \Omega_\Lambda^0 \approx 1

This Universe is therefore hyperbolic[1]. The first Friedmann equation is written:

a˙2a2=H02Ωk0a02a2=H02a02a2\frac{\dot{a}^2}{a^2} = H_0^2 \Omega_k^0 \frac{a_0^2}{a^2} = H_0^2 \frac{a_0^2}{a^2}

then:

a˙=a02H02=a0H0\dot a = \sqrt{a_0^2 H_0^2} = a_0 H_0

Integration therefore gives a Universe expanding at constant velocity:

a(t)=a0H0ta(t) = a_0 H_0 t

2Multi-component models

Modern cosmology was born with General Relativity. Since the writing of these equations, scientists have begun to mathematically describe the universe as a physical system. Many models have been proposed to describe the different histories of the universe.

Eddington-Lemaître model (1927)

Solution to Exercise 1
  1. In the Lemaître matter-only model, the first Friedmann equation is written:

a˙2a2=H02[Ωm0(a0a)3+ΩΛ0+Ωk0(a0a)2]a˙2=H02[Ωm0a03a+ΩΛ0a2+Ωk0a02]\frac{\dot{a}^2}{a^2} = H_0^2\left[\Omega_m^0 \left(\frac{a_0}{a}\right)^{3} + \Omega_\Lambda^0 + \Omega_k^0 \left(\frac{a_0}{a}\right)^{2}\right] \Leftrightarrow \dot{a}^2 = H_0^2\left[\Omega_m^0 \frac{a_0^3}{a} + \Omega_\Lambda^0 a^2 + \Omega_k^0 a_0^2 \right]

At t0t\approx 0, the Universe was extremely small so the matter term dominates:

a˙2H02[Ωm0a03a]aa0a˙a0=H0Ωm0a(t)a0=(32H0Ωm0t)2/3\dot a^2 \approx H_0^2\left[\Omega_m^0 \frac{a_0^3}{a}\right] \Leftrightarrow \sqrt{\frac{a}{a_0}}\frac{\dot{a}}{a_0}= H_0 \sqrt{\Omega_m^0} \Leftrightarrow \frac{a(t)}{a_0} = \left(\frac{3}{2}H_0\sqrt{\Omega_m^0}t\right)^{2/3}
  1. Then, after a certain time, aa becomes large and the cosmological constant term dominates:

a˙2H02(ΩΛ0a2)a˙=H0ΩΛ0a(t)a(t)eH0ΩΛ0t\dot{a}^2 \approx H_0^2\left(\Omega_\Lambda^0 a^2\right) \Leftrightarrow \dot{a}= H_0 \sqrt{\Omega_\Lambda^0} a(t) \Rightarrow a(t) \propto e^{H_0\sqrt{\Omega_\Lambda^0}t}
  1. By differentiating equation (9), we find that:

2a˙a¨=H02[a˙Ωm0a03a2+2a˙aΩΛ0]a¨a0=H022[2ΩΛ0(aa0)Ωm0(a0a)2]2\dot{a}\ddot{a} = H_0^2\left[ -\dot{a}\Omega_m^0 \frac{a_0^3 }{a^{2}} + 2 \dot{a} a \Omega_\Lambda^0 \right] \Leftrightarrow \frac{\ddot{a}}{a_0} = \frac{H_0^2}{2}\left[2 \Omega_\Lambda^0 \left(\frac{a}{a_0}\right) - \Omega_m^0\left(\frac{a_0}{a}\right)^2\right]

When aa is small, we find that a¨\ddot{a} is negative and the expansion decelerates. However, when aa is large, a¨>0\ddot{a}>0 and the expansion of the universe accelerates. The transition occurs at:

a¨=00=H022[2ΩΛ0aa0Ωm0a02a2]aa0=(Ωm02ΩΛ0)1/3\ddot{a}=0 \Leftrightarrow 0=\frac{H_0^2}{2}\left[2 \Omega_\Lambda^0 \frac{a_*}{a_0} - \frac{\Omega_m^0a_0^2}{a_*^2}\right] \Leftrightarrow \frac{a_*}{a_0} = \left( \frac{\Omega_m^0}{2\Omega_\Lambda^0}\right)^{1/3}

For the Λ\LambdaCDM model with Ωm00.3\Omega_m^0\approx 0.3 and ΩΛ00.7\Omega_\Lambda^0\approx 0.7, we have a/a00.6a_*/a_0 \approx 0.6 hence a transition redshift at z0.67z\approx 0.67.

Λ\LambdaCDM

The expansion of the Universe is today well described by the flat Λ\LambdaCDM model (Ωk0=0\Omega_k^0=0). The proportions of each of these components are today evaluated at Planck Collaboration et al. (2020):

ΩΛ0=0.685,Ωm0=0.315\Omega_\Lambda^0 = 0.685,\quad \Omega_m^0=0.315

Concerning cold matter, this can be separated into two contributions: dark matter Ωc0=0.264\Omega_{c}^0=0.264 and baryonic matter[2] Ωb0=0.049\Omega_b^0=0.049. With the CMB temperature, the proportion of relativistic matter is evaluated to Ωr05×105\Omega_r^0 \approx 5\times 10^{-5} today (see CMB chapter).

3Mechanical analogy

Solution to Exercise 2
  1. In terms of Ωi0\Omega_i^0, the first Friedmann equation is written:

H2=(a˙a)2=H02(Ωm0a3+Ωr0a4+ΩΛ0+Ωk0a2)H^2 = \left(\frac{\dot{a}}{a}\right)^2 = H_0^2 \left( \frac{\Omega_m^0}{a^3} + \frac{\Omega_r^0}{a^4} + \Omega_\Lambda^0 + \frac{\Omega_k^0}{a^2} \right)

which gives

12Ωk0=12a˙2H0212Ωm0a12Ωr0a212ΩΛ0a2\frac{1}{2}\Omega_k^0 = \frac{1}{2}\frac{\dot{a}^2}{H_0^2} - \frac{1}{2}\frac{\Omega_m^0}{a} - \frac{1}{2}\frac{\Omega_r^0}{a^2} - \frac{1}{2}\Omega_\Lambda^0 a^2

This last equation resembles the mechanical energy conservation equation for a massive body following one-dimensional motion. Let’s make the analogy:

  • 12Ωk0\frac{1}{2}\Omega_k^0 is constant with aa can be identified as the conserved mechanical energy of the massive body

  • 12a˙2H02\frac{1}{2}\frac{\dot{a}^2}{H_0^2} represents the kinetic energy of the massive body.

  • 12Ωm0a- \frac{1}{2}\frac{\Omega_m^0}{a} resembles a gravitational potential centered around a=0a=0.

  • 12Ωr0a2 -\frac{1}{2}\frac{\Omega_r^0}{a^2} is another type of attractive potential.

  • 12ΩΛ0a2- \frac{1}{2}\Omega_\Lambda^0 a^2 is an inverted harmonic potential (repulsive) centered around a=0a=0.

  1. a¨H02=12Ωm0a2Ωr0a3+ΩΛ0a\frac{\ddot{a}}{H_0^2} = - \frac{1}{2}\frac{\Omega_m^0}{a^2 } -\frac{\Omega_r^0}{a^3 } + \Omega_\Lambda^0 a

This equation resembles Newton’s law applied to a massive body in one-dimensional motion. Let’s make the analogy:

  • a¨H02\frac{\ddot{a}}{H_0^2} acceleration of the massive body

  • 12Ωm0a2- \frac{1}{2}\frac{\Omega_m^0}{a^2 } gravitational force (attractive)

  • +ΩΛ0a+ \Omega_\Lambda^0 a repulsive elastic force

Let’s define:

Veff(a)=12Ωm0a12ΩΛ0a2V_{\rm eff}(a) = - \frac{1}{2}\frac{\Omega_m^0}{a} - \frac{1}{2}\Omega_\Lambda^0 a^2
  1. In this universe model, we have ΩΛ0=Ωm0/2\Omega_\Lambda^0 = \Omega_m^0 / 2 and:

Veff(a)=12Ωm0a14Ωm0a2V_{\rm eff}(a) = - \frac{1}{2}\frac{\Omega_m^0}{a} - \frac{1}{4}\Omega_m^0 a^2
dVeffda=0(1a2a)Ωm0=0a=1 (today)\frac{\dd V_{\rm eff} }{\dd a}= 0 \Rightarrow \left(\frac{1}{a^2}-a\right)\Omega_m^0 = 0 \Rightarrow a=1\text{ (today)}

At a=1a=1 or t=0t=0, the first Friedmann equation gives:

1=Ωm0+ΩΛ0+Ωk0Ωk0=132Ωm01 = \Omega_m^0 + \Omega_\Lambda^0 + \Omega_k^0 \Rightarrow \Omega_k^0 = 1 - \frac{3}{2}\Omega_m^0

The model is spherical so Ωk0=kc2/H02<0\Omega_k^0 = -k c^2 / H_0^2 < 0 with k=+1k=+1 which implies that Ωm0>2/3\Omega_m^0 > 2/3. In Einstein’s Universe, Ωm0=1\Omega_m^0=1.

<Figure size 640x480 with 1 Axes>

Figure 1:Potential energies in the case of a spherical universe with Ωm0=1\Omega_m^0=1.

According to figure Figure 1, Einstein’s solution at a=a0a=a_0 is unstable.

Table 1:Potential energies in the case of matter-only models with different curvatures: (top left), Ωm0=1.5k=+1\Omega_m^0=1.5\Rightarrow k=+1 (top right), Ωm0=0.5k=1\Omega_m^0=0.5\Rightarrow k=-1 (bottom)

Ωm0=1k=0\Omega_m^0=1\Rightarrow k=0

Ωm0=1.5k=+1\Omega_m^0=1.5\Rightarrow k=+1

Ωm0=0.5k=1\Omega_m^0=0.5\Rightarrow k=-1

In these models, the curvature is again given by:

1=Ωm0+Ωk0Ωk0=1Ωm0{k=+1 if Ωm0>1k=0 if Ωm0=1k=1 if Ωm0<11 = \Omega_m^0 + \Omega_k^0 \Rightarrow \Omega_k^0 = 1 -\Omega_m^0 \Rightarrow \left\lbrace\begin{array}{ll} k=+1 & \text{ if } \Omega_m^0 > 1\\ k=0 & \text{ if } \Omega_m^0 = 1 \\ k=-1 & \text{ if } \Omega_m^0 < 1 \end{array}\right.

By analyzing the three plots in figure Table 1, we can say that a spherical universe composed only of matter will necessarily collapse at some point, regardless of its initial conditions (necessity for Einstein to add the cosmological constant). A flat expanding universe extends indefinitely and asymptotically stops its expansion at tt\rightarrow \infty. A hyperbolic expanding universe also extends to infinity.

  1. The transition scale factor is given by:

dVeffda=0a=(Ωm02ΩΛ0)1/3\frac{d V_{\rm eff} }{da}= 0 \rightarrow a_* = \left(\frac{\Omega_m^0}{2 \Omega_\Lambda^0}\right)^{1/3}

Table 2:Potential energies in the case of Λ\LambdaCDM models with different parameters

Ωm0=0.3,ΩΛ0=0.7\Omega_m^0=0.3, \Omega_\Lambda^0=0.7

Ωm0=0.3,ΩΛ0=1.5\Omega_m^0=0.3, \Omega_\Lambda^0=1.5

Ωm0=0.3,ΩΛ0=0.5\Omega_m^0=0.3, \Omega_\Lambda^0=0.5

Ωm0=0.3,ΩΛ0=0.7\Omega_m^0=0.3, \Omega_\Lambda^0=-0.7

Depending on the parameter values, the transition scale occurs in the future or in the past. If the cosmological constant is positive, expanding universes have decelerated expansion and, after the transition scale, accelerated expansion. If the cosmological constant is negative, the universe must collapse after some time.

Why is the Universe therefore expanding today? This depends entirely on initial conditions, so in particular because the universe was born from a Big Bang. And why was there a Big Bang? One can let one’s imagination run free: brane collisions, God, pan-dimensional mice... but the answer is not (yet) given by physical sciences.

4Evolution of cosmological parameters

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Figure 2:Evolution of cosmological parameters.

Footnotes
  1. The sign of kk is the inverse of the sign of Ωk0\Omega_k^0.

  2. Baryonic matter is ordinary matter composed of protons and neutrons. Electrons are as numerous as protons but 2000 times lighter, so they barely contributes to Ωb0\Omega_b^0.

References
  1. Planck Collaboration, Aghanim, N., Akrami, Y., Ashdown, M., Aumont, J., Baccigalupi, C., Ballardini, M., Banday, A. J., Barreiro, R. B., Bartolo, N., Basak, S., Battye, R., Benabed, K., Bernard, J.-P., Bersanelli, M., Bielewicz, P., Bock, J. J., Bond, J. R., Borrill, J., … Zonca, A. (2020). Planck 2018 results - VI. Cosmological parameters. A&A, 641, A6. 10.1051/0004-6361/201833910
  2. Balbinot, R., Bergamini, R., & Comastri, A. (1988). Solution of the Einstein-Strauss problem with a \ensuremathΛ term. \prd, 38(8), 2415–2418. 10.1103/PhysRevD.38.2415
  3. Martin, J. (2012). Everything You Always Wanted To Know About The Cosmological Constant Problem (But Were Afraid To Ask). Comptes Rendus Physique, 89. http://www.sciencedirect.com/science/article/pii/S1631070512000497%20http://arxiv.org/abs/1205.3365
  4. Weinberg, S. (1989). The cosmological constant problem. Reviews of Modern Physics, 61(1), 1–23. 10.1103/RevModPhys.61.1